Optimal. Leaf size=214 \[ \frac{\left (27-2 \sqrt{5}\right ) \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right ),\frac{1}{2}\right )}{60\ 5^{3/4} \sqrt{x^4+5}}+\frac{9 \sqrt{x^4+5} x}{50 \left (x^2+\sqrt{5}\right )}-\frac{9 \sqrt{x^4+5}}{50 x}-\frac{\sqrt{x^4+5}}{15 x^3}+\frac{3 x^2+2}{10 \sqrt{x^4+5} x^3}-\frac{9 \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{10\ 5^{3/4} \sqrt{x^4+5}} \]
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Rubi [A] time = 0.107847, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {1278, 1282, 1198, 220, 1196} \[ \frac{9 \sqrt{x^4+5} x}{50 \left (x^2+\sqrt{5}\right )}-\frac{9 \sqrt{x^4+5}}{50 x}-\frac{\sqrt{x^4+5}}{15 x^3}+\frac{3 x^2+2}{10 \sqrt{x^4+5} x^3}+\frac{\left (27-2 \sqrt{5}\right ) \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{60\ 5^{3/4} \sqrt{x^4+5}}-\frac{9 \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{10\ 5^{3/4} \sqrt{x^4+5}} \]
Antiderivative was successfully verified.
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Rule 1278
Rule 1282
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{2+3 x^2}{x^4 \left (5+x^4\right )^{3/2}} \, dx &=\frac{2+3 x^2}{10 x^3 \sqrt{5+x^4}}-\frac{1}{10} \int \frac{-10-9 x^2}{x^4 \sqrt{5+x^4}} \, dx\\ &=\frac{2+3 x^2}{10 x^3 \sqrt{5+x^4}}-\frac{\sqrt{5+x^4}}{15 x^3}+\frac{1}{150} \int \frac{135-10 x^2}{x^2 \sqrt{5+x^4}} \, dx\\ &=\frac{2+3 x^2}{10 x^3 \sqrt{5+x^4}}-\frac{\sqrt{5+x^4}}{15 x^3}-\frac{9 \sqrt{5+x^4}}{50 x}-\frac{1}{750} \int \frac{50-135 x^2}{\sqrt{5+x^4}} \, dx\\ &=\frac{2+3 x^2}{10 x^3 \sqrt{5+x^4}}-\frac{\sqrt{5+x^4}}{15 x^3}-\frac{9 \sqrt{5+x^4}}{50 x}-\frac{9 \int \frac{1-\frac{x^2}{\sqrt{5}}}{\sqrt{5+x^4}} \, dx}{10 \sqrt{5}}-\frac{1}{150} \left (10-27 \sqrt{5}\right ) \int \frac{1}{\sqrt{5+x^4}} \, dx\\ &=\frac{2+3 x^2}{10 x^3 \sqrt{5+x^4}}-\frac{\sqrt{5+x^4}}{15 x^3}-\frac{9 \sqrt{5+x^4}}{50 x}+\frac{9 x \sqrt{5+x^4}}{50 \left (\sqrt{5}+x^2\right )}-\frac{9 \left (\sqrt{5}+x^2\right ) \sqrt{\frac{5+x^4}{\left (\sqrt{5}+x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{10\ 5^{3/4} \sqrt{5+x^4}}+\frac{\left (27-2 \sqrt{5}\right ) \left (\sqrt{5}+x^2\right ) \sqrt{\frac{5+x^4}{\left (\sqrt{5}+x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{60\ 5^{3/4} \sqrt{5+x^4}}\\ \end{align*}
Mathematica [C] time = 0.0287845, size = 54, normalized size = 0.25 \[ -\frac{9 x^2 \, _2F_1\left (-\frac{1}{4},\frac{3}{2};\frac{3}{4};-\frac{x^4}{5}\right )+2 \, _2F_1\left (-\frac{3}{4},\frac{3}{2};\frac{1}{4};-\frac{x^4}{5}\right )}{15 \sqrt{5} x^3} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.019, size = 192, normalized size = 0.9 \begin{align*} -{\frac{3}{25\,x}\sqrt{{x}^{4}+5}}-{\frac{3\,{x}^{3}}{50}{\frac{1}{\sqrt{{x}^{4}+5}}}}+{\frac{{\frac{9\,i}{250}}}{\sqrt{i\sqrt{5}}}\sqrt{25-5\,i\sqrt{5}{x}^{2}}\sqrt{25+5\,i\sqrt{5}{x}^{2}} \left ({\it EllipticF} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ) -{\it EllipticE} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ) \right ){\frac{1}{\sqrt{{x}^{4}+5}}}}-{\frac{x}{25}{\frac{1}{\sqrt{{x}^{4}+5}}}}-{\frac{2}{75\,{x}^{3}}\sqrt{{x}^{4}+5}}-{\frac{\sqrt{5}}{375\,\sqrt{i\sqrt{5}}}\sqrt{25-5\,i\sqrt{5}{x}^{2}}\sqrt{25+5\,i\sqrt{5}{x}^{2}}{\it EllipticF} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ){\frac{1}{\sqrt{{x}^{4}+5}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{3 \, x^{2} + 2}{{\left (x^{4} + 5\right )}^{\frac{3}{2}} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{x^{4} + 5}{\left (3 \, x^{2} + 2\right )}}{x^{12} + 10 \, x^{8} + 25 \, x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 8.12264, size = 80, normalized size = 0.37 \begin{align*} \frac{3 \sqrt{5} \Gamma \left (- \frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{4}, \frac{3}{2} \\ \frac{3}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{100 x \Gamma \left (\frac{3}{4}\right )} + \frac{\sqrt{5} \Gamma \left (- \frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{3}{4}, \frac{3}{2} \\ \frac{1}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{50 x^{3} \Gamma \left (\frac{1}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{3 \, x^{2} + 2}{{\left (x^{4} + 5\right )}^{\frac{3}{2}} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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